Найти область определения функции
[tex]y= \sqrt{1- \frac{13}{x}+ \frac{30}{x^{2} } } [/tex]
[tex]y= \sqrt{1- \frac{13}{x}+ \frac{30}{x^{2} } } [/tex]
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1 - 13/x + 30/x² >=0x² - 13x + 30 >= 0
(x - 10)(x - 3)>=0 при этом x не равен 0.
Область определения x э (- бесконечности;0) U (0; 3] U [10; +
бесконечности)
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