Решите неравенства
[tex]1) \sqrt[3]{x+2} \leq -5[/tex]
[tex]2) \sqrt{2x+1} \ \textgreater \ 8[/tex]
[tex]3)(x-12) \sqrt{x-3} \leq 0[/tex]
[tex]1) \sqrt[3]{x+2} \leq -5[/tex]
[tex]2) \sqrt{2x+1} \ \textgreater \ 8[/tex]
[tex]3)(x-12) \sqrt{x-3} \leq 0[/tex]
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