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D1g
@D1g
July 2022
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[tex]sin(x- \pi /4)=1/ \sqrt{2} [/tex]
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granny23
Значит x-пи/4= пи/4+2*пи*k, k= 0, +-1? +-2,...
и x-пи/4= 3*пи/4+2*пи*k, k= 0, +-1? +-2,... откуда
x1=пи/2+2*пи*k, k= 0, +-1? +-2,...
x2=пи+2*пи*k, k= 0, +-1? +-2,...
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Answers & Comments
и x-пи/4= 3*пи/4+2*пи*k, k= 0, +-1? +-2,... откуда
x1=пи/2+2*пи*k, k= 0, +-1? +-2,...
x2=пи+2*пи*k, k= 0, +-1? +-2,...