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Дмитрий222222
@Дмитрий222222
July 2022
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Решите уравнение [tex] 2 cos^{2} x-5cosx+3=0[/tex]
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sedinalana
Verified answer
Cosx=a
2a²-5a+3=0
D=25-24=1
a1=(5-1)/4=1⇒cosx=1⇒x=2πn,n∈z
a2=(5+1)/4=1,5⇒cosx=1,5>1 нет решения
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Answers & Comments
Verified answer
Cosx=a2a²-5a+3=0
D=25-24=1
a1=(5-1)/4=1⇒cosx=1⇒x=2πn,n∈z
a2=(5+1)/4=1,5⇒cosx=1,5>1 нет решения