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July 2022 1 3 Report

Помогите решить примеры по дз хотябы один из них
1. [tex]\frac{9}{7-4\sqrt{3} }[/tex]

3.[tex]\frac{b-3}{b-2\sqrt{3b}+3 }[/tex]

4.[tex]\frac{132a}{\sqrt{11} }[/tex]

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Universalka

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$1)\frac{9}{7-4\sqrt{3}}=\frac{9*(7+4\sqrt{3})}{(7-4\sqrt{3})(7+4\sqrt{3})}=\frac{9*(7+4\sqrt{3})}{7^{2}-(4\sqrt{3})^{2}}=\frac{9(7+4\sqrt{3})}{49-48}=9(7+4\sqrt{3})$

$3)\frac{b-3}{b-2\sqrt{3b} +3}=\frac{(\sqrt{b})^{2}-(\sqrt{3})^{2}}{(\sqrt{b})^{2}-2\sqrt{b}*\sqrt{3}+(\sqrt{3})^{2}} =\frac{(\sqrt{b}-\sqrt{3})(\sqrt{b}+\sqrt{3})}{(\sqrt{b}-\sqrt{3})^{2}} =\frac{\sqrt{b}+\sqrt{3}}{\sqrt{b}-\sqrt{3}} =\frac{(\sqrt{b}+\sqrt{3})*(\sqrt{b}+\sqrt{3})}{(\sqrt{b}-\sqrt{3})*(\sqrt{b}+\sqrt{3})} =\frac{(\sqrt{b}+)\sqrt{3})^{2} }{b-3}$

$4)\frac{132a}{\sqrt{11}}=\frac{132a*\sqrt{11}}{\sqrt{11}*\sqrt{11}}=\frac{132a*\sqrt{11}}{(\sqrt{11})^{2}}=\frac{132a*\sqrt{11}}{11}=12\sqrt{11}a$

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jeedkinds July 2022 | 0 Ответы

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