October 2021 1 30 Report
50 баллов! Срочно! Решить неравенства! С подробным решением!
[tex] \sqrt{ {x}^{2} + 1 } > - 2[/tex]
[tex] \sqrt{x + 1} < - 2[/tex]
[tex] \frac{1}{ \sqrt{3 - x} } > 0[/tex]
[tex] \sqrt{x} > \sqrt{2x - 3} [/tex]
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