Решите [tex]7(2x-1)-6(11-x)=3(x+4)[/tex] и [tex](x-3)(x-4)=x^2+2x-11[/tex]. Created by frozenolaf1. algebra-ru

tex]...

frozenolaf1 @frozenolaf1

July 2022 1 12 Report

Решите
[tex]7(2x-1)-6(11-x)=3(x+4)[/tex]
и
[tex](x-3)(x-4)=x^2+2x-11[/tex]

Answers & Comments

Artem112

Verified answer

$7(2x-1)-6(11-x)=3(x+4) 
\\\
14x-7-66+6x=3x+12
\\\
17x=85
\\\
x=5$

$(x-3)(x-4)=x^2+2x-11
\\\
x^2-3x-4x+12=x^2+2x-11
\\\
-9x=-23
\\\
x= \cfrac{23}{9}$

2 votes Thanks 1

sdelajte sintaksicheskij razbor etih dvuh predlozhenij 1 esli chelovek popadaet v

Answer

frozenolaf1 August 2022 | 0 Ответы

nomer 505 punkt 1 rimskaya cifra 3 punkt 2 ves abvg

Answer

frozenolaf1 August 2022 | 0 Ответы

n288 bv n289 ves n290b reshite pozhalujsta

Answer

frozenolaf1 August 2022 | 0 Ответы

skolko bolshih i malenkih pugovic vmeste trebuetsya dlya 8 pidzhakovesli k kazhdo

Answer

Answers & Comments

Verified answer

reshite nomer 120

reshite nomer 28 pozhalujsta

reshite pozhalujsta nomer 5020ffbfc841f7410f78a03bf9dd12f50 19516

pomogite nomer 186

pomogite reshit 139

pomogite reshit 141 nomer 333

sdelajte sintaksicheskij razbor etih dvuh predlozhenij 1 esli chelovek popadaet v

nomer 505 punkt 1 rimskaya cifra 3 punkt 2 ves abvg

n288 bv n289 ves n290b reshite pozhalujsta

skolko bolshih i malenkih pugovic vmeste trebuetsya dlya 8 pidzhakovesli k kazhdo

рекомендуемые вопросы

Helpful Links

Helpful Social