Решите математика.
1)cosx=√2
2)sinx= [tex] \frac{1}{2} [/tex]
3)cos (x-П/3)=√2
4)tgx=[tex] \frac{1}{4} [/tex]
1)cosx=√2
2)sinx= [tex] \frac{1}{2} [/tex]
3)cos (x-П/3)=√2
4)tgx=[tex] \frac{1}{4} [/tex]
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Answers & Comments
2)sinx=1/2, x=((-1)^n)*arcsin(1/2)+πk=((-1)^n)*(π/6)) +πk , k∈Z
3) x=∅ см.п.1
4)х=arctg(1/4)+πk,k∈Z