tex])...

July 2022 1 15 Report

Найдите значение выражения которое указано ниже

y=39cos(2artg1+arccos[tex] \frac{5}{13} [/tex]).

Answers & Comments

andry444 $=39cos( \frac{ \pi }{2}+arccos \frac{5}{13} )=-39sin(arccos \frac{5}{13})= \\ =-39* \sqrt{1-cos^2(arccos\frac{5}{13})} =-39* \sqrt{1- \frac{25}{169} }=-39* \frac{12}{13}=-36$

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simple13 Спасибо,2-рой раз выручаешь ;)

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2- acrtg 4)=...

30 ballovsostavte esli vozmozhno uravneniya gidrolizamolekulyarnye i ionno molek

50 ballovhimiya tri zadaniya na temu ovr

70 ballovhimiya 3 zadaniya ochen srochno

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cost 4picos t ili cos t

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