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babochalosyasha
@babochalosyasha
July 2022
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Внесите множитель под знак корня, если известно, что а<0
[tex]a \sqrt{12} \\ - a \sqrt{5} \\ 3a \sqrt{2} \\ - 2a \sqrt{7} [/tex]
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Слоняра70
Решается так. Если что-то непонятно, напиши в комментариях, я отвечу
2 votes
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