Решите пожалуйста тригонометрические уравнения с arccos\sin
\tg.Заранее спасибо.
[tex]3.) \frac{4}{5}arccos \frac{1}{2} - \frac{1}{3} arctg \sqrt{3} ;
4.) \frac{1}{3} arccos \frac{ \sqrt{2} }{2} [/tex]
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