(x+1)^(1/6) = t
t^2-3t+2=0
D=1
t1=2 t2=1
(x+1)^(1/6) = 1
x+1 = 1 x1=0
(x+1)^(1/6) = 2
x+1 = 2^6
x+1=64
x2=63
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(x+1)^(1/6) = t
t^2-3t+2=0
D=1
t1=2 t2=1
(x+1)^(1/6) = 1
x+1 = 1 x1=0
(x+1)^(1/6) = 2
x+1 = 2^6
x+1=64
x2=63