tex]...

August 2021 1 39 Report

Как решаются подобные примеры? С применением свойств арифметического корня.
[tex] \frac{ \sqrt[8]{a} \sqrt[5]{a} }{ \sqrt[10]{ {a}^{5} } } \\ [/tex]
[tex] \frac{ \sqrt[4]{ {a}^{2} } \sqrt[5]{a} }{ \sqrt[8]{ {a}^{5} } } \\ [/tex]

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QDominus

$\frac{ \sqrt[8]{a} \sqrt[5]{a} }{ \sqrt[10]{ {a}^{5} } } = \frac{ {a}^{ \frac{1}{8}} {a}^{ \frac{1}{5} } }{ {a}^{ \frac{5}{10} } } = \frac{ {a}^{ \frac{1}{8} + \frac{1}{5} } }{ {a}^{ \frac{1}{2} } } = \frac{ {a}^{ \frac{13}{40} } }{ {a}^{ \frac{1}{2} } } = {a}^{ \frac{13}{40} - \frac{1}{2} } = {a}^{ - \frac{7}{40} }$

$\frac{ \sqrt[4]{ {a}^{2} } \sqrt[5]{a} }{ \sqrt[8]{ {a}^{5} } } = \frac{ {a}^{ \frac{2}{4} } {a}^{ \frac{1}{5} } }{ {a}^{ \frac{5}{8} } } = \frac{ {a}^{ \frac{1}{2} + \frac{1}{5} } }{ {a}^{ \frac{5}{8} } } = \frac{ {a}^{ \frac{7}{10} } }{ {a}^{ \frac{5}{8} } } = {a}^{ \frac{7}{10} - \frac{5}{8} } = {a}^{ \frac{3}{40} }$

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