Найти значение выражений: (240,30 и -600 в градусах)
[tex](8 \sqrt12} ) ^{2}/24[/tex]
[tex]-2sin(240)/cos(30)[/tex]
[tex]-2 \sqrt{3}sin(-600) [/tex]
[tex](8 \sqrt12} ) ^{2}/24[/tex]
[tex]-2sin(240)/cos(30)[/tex]
[tex]-2 \sqrt{3}sin(-600) [/tex]
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