НАРОД, ПОМОГИТЕ СДЕЛАТЬ ВСЕ. ОТМЕЧУ ЛУЧШИМ!
Докажите тождество:
а) [tex]2sin( \frac{ \pi }{6}+ \alpha )- \sqrt{3} sin \alpha =cos \alpha [/tex]
б) [tex]sin( \alpha + \beta )sin( \alpha - \beta )+sin ^{2} \beta =sin^2 \alpha [/tex]
в) [tex] \frac{sin( \alpha + \beta )-2sin \alpha cos \beta }{2cos \alpha cos \beta -cos( \alpha + \beta )} =tg( \beta - \alpha )[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2024 SCHOLAR.TIPS - All rights reserved.