tex]...

July 2022 1 9 Report

Найдите область определения функции :
[tex]y= \frac{ \sqrt{x+12} }{ x^{2-1} } [/tex]
[tex]y= \frac{x- \sqrt{-x^{2}-7x+8 } }{1+ \sqrt{x+3} } [/tex]

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Artem112

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$y= \frac{ \sqrt{x+12} }{ x^{2-1} }= \frac{ \sqrt{x+12} }{ x }
\\\
 \left \{ {{ x+12 \geq 0} \atop {x \neq 0}} \right.
\\\
 \left \{ {{ x \geq -12} \atop {x \neq 0}} \right.
\\\
x\in(-12; 0)\cup(0; +\infty)$

$y= \frac{x- \sqrt{-x^{2}-7x+8 } }{1+ \sqrt{x+3} } 
\\\
 \left \{ {{-x^{2}-7x+8 \geq 0} \atop {x+3 \geq 0}} \right. 
\\\
 \left \{ {{x^2+7x-8 \leq 0} \atop {x \geq -3}} \right. 
\\\
 \left \{ {{-8 \leq x \leq 1} \atop {x \geq -3}} \right. 
\\\
-3 \leq x \leq 1$

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Laxix333 ладно,щас разберусь))) xd)

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