Значение выражения [tex] \frac{1}{3}|x|+ \frac{1}{2}|x| [/tex] равно 1, если: а)x=±[tex] \frac{5}{6}[/tex]; б)x=±1,2; в)x=±[tex] \frac{1}{3} [/tex]
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|x|*((1/3)+(1/2))=1|x|*(2+3)/6=1
|x|*5/6=1
|x|*5=6
|x|=6/5
x=+-6/5=+-1,2
Ответ: б)