Home
О нас
Products
Services
Регистрация
Войти
Поиск
anasya2
@anasya2
June 2022
1
0
Report
Помогите решить уравнение [tex](2x-6)* \sqrt{- x^{2}+2x } =0[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
lubovlubvasil
решить уравнение
(2х-6)
=0
ОДЗ: -
+2х≥0, х∈[0, 2]
2х-6=0 или -
+2х=0
х=3 или х( - х+2)=0, т.е. х=0, х=2
3
не принадлежит [0,2]
ответ: 0, 2
2 votes
Thanks 1
More Questions From This User
See All
anasya2
August 2022 | 0 Ответы
reshite uravnenie 2 x4 x3 0
Answer
anasya2
May 2021 | 0 Ответы
reebyayata ooooochen srochnooo a i b pomogite pozhalujsta
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
ОДЗ: - +2х≥0, х∈[0, 2]
2х-6=0 или - +2х=0
х=3 или х( - х+2)=0, т.е. х=0, х=2
3 не принадлежит [0,2]
ответ: 0, 2