ПОМОГИТЕ СРОЧНО!!![tex] \frac{1}{4} \sqrt{16x} + \frac{2}{5} \sqrt{25x} = 1[/tex]. Created by jaraalera9. algebra-ru

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ПОМОГИТЕ СРОЧНО!!!
[tex] \frac{1}{4} \sqrt{16x} + \frac{2}{5} \sqrt{25x} = 1[/tex]

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Matematiktm

Ответ:

Объяснение:

$\frac{1}{4} \sqrt{16x} + \frac{2}{5} \sqrt{25x} = 1;\\ \frac{1}{4} *4\sqrt{x}+ \frac{2}{5} *5\sqrt{x} = 1;\\\\\sqrt{x} + 2\sqrt{x} = 1;\\\\3\sqrt{x} = 1;\\\\\sqrt{x} = \frac{1}{3} \\x=\frac{1}{9}$

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