Докажите, что: [tex] \sqrt3} + 4 = \sqrt{8 \sqrt{3} +19[/tex]. Created by makarevig. algebra-ru

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makarevig @makarevig

August 2022 1 5 Report

Докажите, что: [tex] \sqrt3} + 4 = \sqrt{8 \sqrt{3} +19[/tex]

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Vladislav006

Verified answer

$\sqrt3} + 4 = \sqrt{8 \sqrt{3} +19$
$(\sqrt3} + 4)^2 = (\sqrt{8 \sqrt{3} +19)^2$
$3 + 8 \sqrt{3} +16 = {8 \sqrt{3} +19$
$3 + 16 = 19 \\ 19 = 19$
значит
$\sqrt3} + 4 = \sqrt{8 \sqrt{3} +19$

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