Составьте уравнения электролитической диссоциации следующих электролитов:
1)[tex]NaHCO_{3}[/tex]
2)[tex]Cu(OH)_{2}[/tex]
3)[tex]Ca(H_{2} PO_{4} )_{2}[/tex]
4)[tex]Fe(OH)_{2} NO_{3}[/tex]
1)[tex]NaHCO_{3}[/tex]
2)[tex]Cu(OH)_{2}[/tex]
3)[tex]Ca(H_{2} PO_{4} )_{2}[/tex]
4)[tex]Fe(OH)_{2} NO_{3}[/tex]
Answers & Comments
Verified answer
1)NaHCO₃ = Na⁺ + HCO₃⁻
HCO₃⁻ = H⁺ + CO₃²⁻
2) Cu(OH)₂ = CuOH⁺ + OH⁻
CuOH⁺ = Cu²⁺ + OH⁻
3) Ca(H₂PO₄)₂ =Ca²⁺ + 2H₂PO₄⁻
H₂PO₄⁻ = H⁺ + HPO₄²⁻
HPO₄²⁻ = H⁺ + PO₄³⁻
4) Fe(OH)₂NO₃ = Fe(OH)₂⁺ + NO₃⁻
Fe(OH)₂⁺ = FeOH²⁺ + OH⁻
FeOH²⁺ = Fe³⁺ + OH⁻