Home
О нас
Products
Services
Регистрация
Войти
Поиск
Алинини
@Алинини
July 2022
1
10
Report
[tex] \left \{ {{16^{-x- \frac{3}{2} } -9*4^{-x-2} +2 \geq 0} \atop Log _{2} \frac{5x+7-2 x^{2} }{4x+1} \leq 1}} \right. [/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
IUV
Verified answer
16^(-x-3/2)-9*4^(-x-2)+2>=0
4^(-2x-3)-9*4^(-x-2)+2>=0
4^(-2x)-36*4^(-x-2)+2*4^3>=0
4^(-x)=t>0
d=36^2-4*2*4^3=28^2
t1=(36+28)/2=32
4^(-x)=t>=32=4^2,5
-x>=2,5
x<=-2,5
log[2]((5x+7-2x^2)/(4x+1)) <=1=log[2](2)
0<(5x+7-2x^2)/(4x+1) <=2
-2,5<=x<-1 или 1<=x<3,5
ответ x=-2,5
1 votes
Thanks 1
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
16^(-x-3/2)-9*4^(-x-2)+2>=04^(-2x-3)-9*4^(-x-2)+2>=0
4^(-2x)-36*4^(-x-2)+2*4^3>=0
4^(-x)=t>0
d=36^2-4*2*4^3=28^2
t1=(36+28)/2=32
4^(-x)=t>=32=4^2,5
-x>=2,5
x<=-2,5
log[2]((5x+7-2x^2)/(4x+1)) <=1=log[2](2)
0<(5x+7-2x^2)/(4x+1) <=2
-2,5<=x<-1 или 1<=x<3,5
ответ x=-2,5