tex]...

Identify @Identify

August 2022 1 5 Report

Интеграл от [tex] \frac{dx}{x^2+6x+25} [/tex]

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NNNLLL54

Verified answer

$\int \frac{dx}{x^2+6x+25}=\int \frac{dx}{(x+3)^2+16}=\frac{1}{4}arctg\frac{x+3}{4}+C$

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