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Lanochka555
@Lanochka555
November 2021
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Помогите, пожалуйста, решить интеграл [tex] \int\limits^2_1 {3x^2-2x+1} \, dx [/tex]
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MizoriesKun
1 находим первообразную для f(x)=3x²-2x+1
F(x)=x³-x²+1
2 F(2)=2³-2²+2=6
F(1)= 1³-1²+1=1
3 F(2)- F(1)=6-1=5
∫²₁ 3x²-2x+1 dx=(x³-x²+1) |₁² = 6-1 =5
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Answers & Comments
F(x)=x³-x²+1
2 F(2)=2³-2²+2=6
F(1)= 1³-1²+1=1
3 F(2)- F(1)=6-1=5
∫²₁ 3x²-2x+1 dx=(x³-x²+1) |₁² = 6-1 =5