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ulzi2001
@ulzi2001
September 2021
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[tex] \frac{ a^{2} -ax}{ a^{2}x-a x^{2} } - \frac{1}{x} [/tex]
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sangers1959
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(a²-ax)/(a²x-ax²)-1/x=a(a-x)/(ax(a-x)-1/x=1/x-1/x=0.
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(a²-ax)/(a²x-ax²)-1/x=a(a-x)/(ax(a-x)-1/x=1/x-1/x=0.