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daniilkey
@daniilkey
October 2021
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В первом и втором случае ОДЗ будет [tex]|2x+4| \neq 0[/tex] ? Или тут вообще нет ограничений?
[tex]\frac{23}{|2x+4|}-12\leq 0\\\frac{23}{|2x+4|} \leq 0[/tex]
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армения20171
23/|2x+4|-12≤0
|2x+4|≠0
x≠-2
ODZ x€(-oo;-2)U(-2;+oo)
(23-12|2x+4l)/|2x+4|≤0
l2x+4l>0
23-12l2x+4|≤0
12l2x+4|≥23
|2x+4|≥23/12
[2x+4≥23/12;x≥-2+23/24;x≥-25/24
[2x+4≤-23/12;x≤-2-23/24;x≤-71/24
___-71/24___-2___-25/24
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Answers & Comments
|2x+4|≠0
x≠-2
ODZ x€(-oo;-2)U(-2;+oo)
(23-12|2x+4l)/|2x+4|≤0
l2x+4l>0
23-12l2x+4|≤0
12l2x+4|≥23
|2x+4|≥23/12
[2x+4≥23/12;x≥-2+23/24;x≥-25/24
[2x+4≤-23/12;x≤-2-23/24;x≤-71/24
___-71/24___-2___-25/24