срочноо решитее [tex] \frac{2a²+5a-12}{2a-3} -a+1[/tex]. Created by Настя0407. algebra-ru

tex]...

Настя0407 @Настя0407

July 2022 1 3 Report

срочноо решитее
[tex] \frac{2a²+5a-12}{2a-3} -a+1[/tex]

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гюйс

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$\frac{2a^{2} +5a-12}{2a-3} -a+1= \frac{2a^{2}+5a-12-(a-1)(2a-3) }{2a-3} = \frac{2 a^{2}+5a-12-2a^{2}+3a+2a-3 }{2a-3}=$ $\frac{10a-15}{2a-3}= \frac{5(2a-3)}{2a-3}=5$

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