помогите!!!! [tex]9^{x} + 3^{x+1} \ \textgreater \ 108[/tex]. Created by llysyak. algebra-ru

tex]...

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Решение смотри в приложении

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$9^x+3 ^{x+1} \ \textgreater \ 108$
$3 ^{2x} +3*3^x-108\ \textgreater \ 0$
$3^x=a$
a²+3a-108>0
a1+a2=-3 U a1*a2=-108
a1=-12 U a2=9
a<-12⇒ $3^x\ \textless \ -12$ нет решения
a>9⇒ $3^x\ \textgreater \ 9$ ⇒x>2
x∈(2;∞)

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