Решите уравнение:
[tex] \frac{3 + x}{3x} = \sqrt{ \frac{1}{9} + \frac{1}{x} \sqrt{ \frac{4}{9} + \frac{2}{ {x}^{2} } } } [/tex]
[tex] \frac{3 + x}{3x} = \sqrt{ \frac{1}{9} + \frac{1}{x} \sqrt{ \frac{4}{9} + \frac{2}{ {x}^{2} } } } [/tex]
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