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milasuper1999
@milasuper1999
August 2021
2
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Помогите, пожалуйста, срочно!!!
[tex] \frac{(x+2)(x-3)}{(x+3)(x-2)} \leq 0[/tex]
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MM18
(x + 2)(x - 3)/(x + 3)(x - 2) <=0
(x + 2)(x - 3) <= 0
x + 2 = 0 x - 3 = 0
x = -2 x = 3
_____-2//////////3_____
(x + 3)(x - 2) < 0
x + 3 = 0 x -2 =0
x = -3 x = 2
____-3///////////////2_____
х Э [-2; 2)
2 votes
Thanks 0
MM18
х Э [-2; 2)
WRT17hk
Критические точки -3,-2, 2 и 3.
f(x) ∈[-3;-2) V [2;3) ≤0
1 votes
Thanks 1
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Answers & Comments
(x + 2)(x - 3) <= 0
x + 2 = 0 x - 3 = 0
x = -2 x = 3
_____-2//////////3_____
(x + 3)(x - 2) < 0
x + 3 = 0 x -2 =0
x = -3 x = 2
____-3///////////////2_____
х Э [-2; 2)
f(x) ∈[-3;-2) V [2;3) ≤0