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afasters
@afasters
July 2022
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Помогите решить задачу!
tg[tex] \alpha [/tex] = 1/3
[tex] \pi \ \textless \ \alpha \ \textless \ \frac{3 \pi }{2} [/tex]
Найти :
[tex]ctg \alpha ,sin \alpha ,cos \alpha [/tex]
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Bronzor1
Tga=1/3
ctga=1/tga=3
cosa=√(1/(1+tg²(x)))=√(9/10)=3/√(10)
sina=√(1-cos²a)=√(1-9/10)=√(1/10)=1/√(10)
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Answers & Comments
ctga=1/tga=3
cosa=√(1/(1+tg²(x)))=√(9/10)=3/√(10)
sina=√(1-cos²a)=√(1-9/10)=√(1/10)=1/√(10)