Как найти производную данной функции? 8*(1/2)^(x-4)+10 [tex]8* (\frac{1}{2})^{x-4} +10[/tex]. Created by ugopek. algebra-ru

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July 2022 1 6 Report

Как найти производную данной функции? 8*(1/2)^(x-4)+10
[tex]8* (\frac{1}{2})^{x-4} +10[/tex]

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tszs62 $8* \frac{1}{2} ^{x-4}+10 \\ 
8* \frac{1}{2} ^{x}* \frac{1}{2}^{4}+10 \\ 
 \frac{8}{16} * \frac{1}{2}^{x}+10 \\ 
 (\frac{1}{2}* \frac{1}{2}^{x}+10)' = \frac{1}{2} * \frac{1}{2}^{x}ln \frac{1}{2}$

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