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1)[tex]6x(0.5+3x)- 15x^{2} =0[/tex]
2)[tex](4-x)(4+x)= x^{2} -2[/tex]
1)[tex]6x(0.5+3x)- 15x^{2} =0[/tex]
2)[tex](4-x)(4+x)= x^{2} -2[/tex]
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3х+18х²-15х²=0
3х²+3х=0
3х(х+1)=0
3х=0 или х+1=0
х=0 х= -1
Ответ:0; -1
(4-х)(4+х)=х²-2
16+4х-4х-х²=х²-2
2х²=18
х²=9
х=3
Ответ:3