tex]...

July 2022 1 3 Report

№3 Сократить дробь
а)[tex]\frac{7+\sqrt{7} }{5\sqrt{7} }[/tex] б)[tex]\frac{16p-5}{4\sqrt{p}-\sqrt{5} }[/tex]
№4 Освободитесь от иррациональности в знаменателе
а)[tex]\frac{4}{2\sqrt{6} }[/tex] б)[tex]\frac{10}{3-\sqrt{5} }[/tex]

Answers & Comments

daraprelj

№3.а) $\displaystyle \frac{7+\sqrt{7} }{5\sqrt{7} } = \frac{\sqrt{7}*(\sqrt{7} +1) }{5\sqrt{7} }=\frac{\sqrt{7} +1 }{5 }$

№3.б) $\displaystyle \frac{16p-5}{4\sqrt{p}-\sqrt{5} } =\frac{(4\sqrt{p}+\sqrt{5} )(4\sqrt{p}-\sqrt{5} )}{4\sqrt{p}-\sqrt{5} } =4\sqrt{p}+\sqrt{5}$

№4.а) $\displaystyle \frac{4}{2\sqrt{6} } *\frac{\sqrt{6}}{\sqrt{6}} =\frac{4\sqrt{6}}{2*6} =\frac{\sqrt{6}}{3}$

№4.б) $\displaystyle \frac{10}{3-\sqrt{5} } *\frac{3+\sqrt{5}}{3+\sqrt{5}}=\frac{10*(3+\sqrt{5})}{(3-\sqrt{5})(3+\sqrt{5})}=\frac{10*(3+\sqrt{5}) }{9-5} =\frac{10*(3+\sqrt{5}) }{4} =\frac{5*(3+\sqrt{5}) }{2} =\frac{15+5\sqrt{3} }{2}$

1 votes Thanks 1

Answers & Comments

tex 9 is how you feel about yourself 10 its impolite to at people 11 th

pozhalujsta pomogite srochno dayu 20 ballov broaden explore unique landmarks wo

pomogite pozhalujsta srochno dayu 15 ballovv treugolnike avs provedena srednyaya lin

tex]...

tex]...

pomogite pozhalujsta dam 30 ballov pzhc014ce26a94f6fee4ad47b3a7c2bfc68 70049

temy sochinenij 1kakuyu rol sygral buran v zhizni petrushi grineva 2pochemu mne n

raskrojte skobki i postavte v past simple ili past continuous 4 when our guest

raskrojte skobki i postavte v past simple ili past continuous 1 they clean t

рекомендуемые вопросы

Helpful Links

Helpful Social