Помогите, 40 баллов!
а)[tex] log_{3}(x+4)= log_{3}(2x-1) [/tex]
б)[tex] log_{2}(x-3)=4 [/tex]
в)[tex] lg(x-1)+lg(x-2,5)=1 [/tex]
г)[tex] log_{5}(x^2-2x+4)= log_{5}(2x^2+5x+10) [/tex]
а)[tex] log_{3}(x+4)= log_{3}(2x-1) [/tex]
б)[tex] log_{2}(x-3)=4 [/tex]
в)[tex] lg(x-1)+lg(x-2,5)=1 [/tex]
г)[tex] log_{5}(x^2-2x+4)= log_{5}(2x^2+5x+10) [/tex]
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Answers & Comments
log(3)(2x-5)(2x-3)=1
(2x-5)(2x-3)=3
4x²-6x-10x+15-3=0
4x²-16x+12=0
x²-4x+3=0
x1+x2=4 U x1*x2=3
x1=1 не удов усл
x2=3
b)lg^2x+4lgx+4-1=0
lg^2x+4lgx+3=0
lgx=a
a2+4a+3=0⇒a1+a2=-4 U a1*a2=3
a1=-3⇒lgx=-3⇒x=0,001
a2=-1⇒lgx=-1⇒x=0,1