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stiklin
@stiklin
June 2022
1
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[tex] \frac{ x^{2} }{x+6}= \frac{1}{2} [/tex]
[tex] \frac{x+2}{x-1} + \frac{x}{x+1} = \frac{6}{ x^{2} -1 } [/tex]
[tex] \frac{ x^{2} -x}{x+3}= \frac{12}{x+3} [/tex]
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05101965nalsur
⇒2х²=х+6,х≠6; 2х²-х-6=0;Д=49;х₁=-1,5,х₂=2..........⇒((х+2)(х+1)+х(х-1)-6) / ((х²-1) =0;х≠1,х≠-1; х²+2х+х+2+х²-х-6) / (х²-1); 2х²+2х-4=0;х≠1,х≠-1; х²+х-2=0; Д=9; х₁=-2; х₂=1-не соответствует.Ответ: -2.............⇒(х²-х-12) / (х+3)=0;х≠-3; х²-х-12=0; Д=49; х₁=-3-не соответствует; х₂=4.Ответ: 4
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