Решите уравнение. Методом интервалов
[tex] \frac{(x-1)^{2}+4(x+1)^{2} }{2} \leq \frac{(3x+1)^{2} }{4} [/tex]
[tex] \frac{(x-1)^{2}+4(x+1)^{2} }{2} \leq \frac{(3x+1)^{2} }{4} [/tex]
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