tex]...

July 2022 1 11 Report

Помогите пожалуйста решить систему показательных уравнений:
[tex] \left \{ {{ 6^{x}+ y =2} \atop { 6^{2x} + 6^{x}=12 }} \right. [/tex]

Answers & Comments

dtnth

Verified answer

Сделаем замену $6^x=t >0; 6^{2x}=(6^x)^2=t^2$

$6^{2x}+6^x=12$
$t^2+t-12=0$
$(t+4)(t-3)=0$
$t+4=0;t_1=-4$
$t-3=0;t_2=3$
$t=3$
$6^x=3;t=log_6 3$
$y=2-6^x=2-3=-1$
решение $(log_6 3;-1)$

0 votes Thanks 0

paskaldano slovo udalit iz nego tretyu bukvuusloviezhelatelno no neobyazat

Answer

xaruno12 August 2022 | 0 Ответы

informaciya o kolichestve zhilcov v kazhdoj iz chetyreh kvartir kazhdogo etazha 12 eta

Answer

xaruno12 August 2022 | 0 Ответы

Answers & Comments

Verified answer

paskaldano slovo udalit iz nego tretyu bukvuusloviezhelatelno no neobyazat

informaciya o kolichestve zhilcov v kazhdoj iz chetyreh kvartir kazhdogo etazha 12 eta

pravilnyj perevod predlozheniya ee ne bylo doma she was not at home she was not

dana fraza cenaya vesh ispravit oshibku v nej paskal

tex]...

there some students in the laboratory now are will be were is s

s slovo v kotorom est zvuk w who allow write one s slovo v ko

s slovo v kotorom bukva e chitaetsya kak q pie diet quite lie s s

s slovo v kotorom net zvuka l cause autumn amount trauma s slov

s slovo gde sochetanie sh chitaetsya kak k chest chalk children ch

рекомендуемые вопросы

Helpful Links

Helpful Social