На помощь. Хоть что-то)) Сократите:
1)[tex] \frac{m^2-4m+4}{(m-4/m)^2} [/tex]
2)([tex]\frac{5}{x-2} [/tex] - x - 2)*[tex] \frac{2-x}{x^2+6x+9} [/tex]
3)(x+[tex] \frac{9}{x-6} [/tex]):[tex] \frac{3x^2-18x+27}{x^2-36} [/tex]
4)[tex] \frac{5}{1+4/x} [/tex]*([tex] \frac{x-4}{x^2+4x} [/tex]-[tex] \frac{16}{16-x^2} [/tex])
1)[tex] \frac{m^2-4m+4}{(m-4/m)^2} [/tex]
2)([tex]\frac{5}{x-2} [/tex] - x - 2)*[tex] \frac{2-x}{x^2+6x+9} [/tex]
3)(x+[tex] \frac{9}{x-6} [/tex]):[tex] \frac{3x^2-18x+27}{x^2-36} [/tex]
4)[tex] \frac{5}{1+4/x} [/tex]*([tex] \frac{x-4}{x^2+4x} [/tex]-[tex] \frac{16}{16-x^2} [/tex])
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Verified answer
По формулам сокращённого умножения.Verified answer
1(m-2)²:(m²-4)/m=(m-2)²*m/(m-2)(m+2)=m(m-2)/(m+2)
2
1)5/(x-2)-(x+2)=(5-x²+4)/(x-2)=(9-x²)/(x-2)=(x²-9)/(2-x)
2)(x-3)(x+3)/(2-x)*(2-x)/(x+3)²=(x-3)/(x+3)
3
1)x-9/(x-6)=(x²-6x+9)/(x-6)=(x-3)²/(x-6)
2)(x-3)²/(x-6):3(x-3)²/(x-6)(x+6)=(x-3)²/(x-6)*(x-6)(x+3)/3(x-3)²=(x+6)/3
4
1)(x-4)/x(x+4)+16/(x-4)(x+4)=(x²-8x+16+16x)/x(x²-16)=(x²+8x+16)/x(x²-16)=
=(x+4)²/[x(x-4)(x+4)]=(x+4)/x(x-4)
2)5/(1+4/x)=5:(x+4)/x=5x/(x+4)
3)(x+4)/x(x-4)*5x/(x+4)=5/(x-4)