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Помогите пожалуйста! Нужно упростить выражение:
[tex] \frac{2sin^{2} }{1+cos( \pi -2 \alpha )}-sin^{2} \alpha =[/tex]

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kmike21

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$\frac{2sin^2a}{1+cos( \pi -2a)} -sin^2a=\frac{2sin^2a}{1-cos2a} -sin^2a= \frac{2sin^2a}{1-cos^2a+sin^2a} -sin^2a= \\ =\frac{2sin^2a}{sin^2a+sin^2a} -sin^2a=1-sin^2a=cos^2a$

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