tex]...

March 2022 1 4 Report

1)[tex] x^{2}-2x-8[/tex]
2)[tex] y^{2}+2y-8[/tex]

Answers & Comments

KirillLity 1)x²-2x-8=0
D=4+4*8=6²
x1=2+6/2=4
x2=2-6/2=-2
x²-2x-8=(x-4)(x+2)
2)y²+2y-8=0
D=4+4*8=6²
y1=-2+6/2=2
y2=-2-6/2=-4
y²+2y-8=(y-2)(y+4)

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