Найдите корни уравнения.
[tex]sin(x) - \frac{1}{\sqrt{3} } sin(2x) = cos(x) - \frac{\sqrt{3} }{2}[/tex]
[tex]sin(x) - \frac{1}{\sqrt{3} } sin(2x) = cos(x) - \frac{\sqrt{3} }{2}[/tex]
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