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[tex] \frac{\sqrt{2} + \sqrt{3}+ \sqrt{16} }{ \sqrt{3}+ \sqrt{2}+6+ \sqrt{32}+ \sqrt{6} }[/tex]
[tex] \frac{\sqrt{2} + \sqrt{3}+ \sqrt{16} }{ \sqrt{3}+ \sqrt{2}+6+ \sqrt{32}+ \sqrt{6} }[/tex]
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=(√2+√3+√16)/(√2+√3+√16+√2√2+√2√3+√2√16)=(√2+√3+√16)/(√2+√3+√16+√2(√2+√3+√16))=(√2+√3+√16)/(1+√2)(√2+√3+√16)=1/(1+√2)=√2-1