tex]...

ruslankyzymadina1 @ruslankyzymadina1

July 2022 1 2 Report

[tex] tg(pi/2+a)*tg(2pi-a)/sin(-a) [/tex]

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NNNLLL54

Verified answer

$\frac{tg(\frac{\pi }{2}+a)\cdot tg(2\pi -a)}{sin(-a)}=\frac{-ctga\cdot tg(-a)}{-sina}=\frac{ctga\cdot (-tga)}{sina}=\frac{-1}{sina}=-coseca$

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