Решите выражение:
[tex] \frac{18}{4 x^{2} +4x+1} - \frac{1}{2 x^{2} -x} = \frac{6}{4 x^{2} -1} [/tex]
[tex] \frac{18}{4 x^{2} +4x+1} - \frac{1}{2 x^{2} -x} = \frac{6}{4 x^{2} -1} [/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
18/(2x+1)²-1/x(2x-1)=6/(2x-1)(2x+1)ОЗ x(2x+1)²(2x-1)≠0⇒x≠0 U x≠-0,5 U x≠0,5
18x(2x-1)-(2x+1)²=6x(2x+1)
36x²-18x-4x²-4x-1-12x²-6x=0
20x²-28x-1=0
D=784+80=864
x1=(28-12√6)/40=(7-3√6)/10
x2=(7+3√6)/10