[tex]5sin2x+5cosx-8sinx-4=0[/tex]. Created by tornado1357. algebra-ru

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tornado1357 @tornado1357

July 2022 1 9 Report

[tex]5sin2x+5cosx-8sinx-4=0[/tex]

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sedinalana

Verified answer

10sinxcosx+5cosx-8sinx-4=0
5cosx(2sinx+1)-4(2sinx+1)=0
(2sinx+1)(5cosx-4)=0
2sinx+1=0
sinx=-1/2
x=(-1)^(n+1)*π/6+πn,n∈z
2cosx-4=0
cosx=0,8
x=+-arccos0,8+2πk,k∈z

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vtoroe zadanie nuzhno reshitpomogite pozhalujtsa

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2sin2x+sinx=4cosx+1...

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