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GAMERKA
@GAMERKA
July 2022
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Помогите решить уравнение![tex]3 \frac{1}{3} x^{2} +3 x-3=0[/tex]
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KarinaYouchi
10\3x^2+3x-3=0 |*3
10x^2+9x-9=0
D=9^2-4*10*(-9)=81+360=441
x1=-9+√441=-9+21=12\20=3\5
2*10 20
x2=-9-√441=-9-21=-30\20=-3\2=-1 1\2
2*10 20
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Answers & Comments
10x^2+9x-9=0
D=9^2-4*10*(-9)=81+360=441
x1=-9+√441=-9+21=12\20=3\5
2*10 20
x2=-9-√441=-9-21=-30\20=-3\2=-1 1\2
2*10 20