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[tex] \sqrt{9- x^{2} } \sqrt{10-3x- x^{2} } =0[/tex]
[tex] \sqrt{9- x^{2} } \sqrt{10-3x- x^{2} } =0[/tex]
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9-х²=0 10-3х-х²≥0 х∈[-5 ; 2] х∈[-3 ; 2 ]
(3-х)(3+х)=0
3-х=0 3+х=0
х=3 х=-3
10-3х-х²=0
-x²-3x+10=0
x²+3x-10=0 D=49 √D=7 x1=-5 x2=2
Ответ: 2 ;-3