Упростите!
1. [tex]( \frac{x+3}{x^2-3x}+ \frac{12}{9-x^2}) : \frac{3}{3+x} [/tex]
2. [tex]( \frac{1}{d} -1) * \frac{4d}{1-d^2} [/tex]
1. [tex]( \frac{x+3}{x^2-3x}+ \frac{12}{9-x^2}) : \frac{3}{3+x} [/tex]
2. [tex]( \frac{1}{d} -1) * \frac{4d}{1-d^2} [/tex]
Answers & Comments
Verified answer