tex]...

ioankorol1549 @ioankorol1549

November 2021 1 15 Report

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[tex] \frac{2x {}^{2} + x - 3 }{x {}^{2} - 1} [/tex]

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сок111213

$\frac{2x {}^{2} + x - 3 }{x {}^{2} - 1} = \frac{2(x - 1)(x + 1.5)}{(x - 1)(x + 1)} = \frac{2(x + 1.5)}{x + 1} = \frac{2x + 3}{x + 1} \\ \\ 2 {x}^{2} + x - 3 = 0 \\ d = 1 {}^{2} - 4 \times 2 \times ( - 3) = 1 + 24 = 25 \: (5) \\ x _{1} = \frac{ - 1 + 5}{4} = \frac{4}{4} = 1 \\ x_{2} = \frac{ - 1 - 5}{4} = - \frac{6}{4} = - \frac{3}{2} = - 1.5 \\ 2x {}^{2} + x - 3 = 2(x - 1)(x + 1.5)$

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